If A and B are two sets, then {tex}A \cap (A \cup B)'{/tex} is equal to
**A. ** B
**B. ** none of these
**C. ** {tex}\emptyset {/tex}
**D. ** A
**Answer : ****Option C**

**Explaination / Solution: **

{tex}A \cap (A \cup B)' = \phi {/tex} since {tex}(A \cup B)'{/tex} Set represent the element which are not belongs to it,so there is no common element with the set A.So the answer is null set

{tex}A \cap (A \cup B)' = \phi {/tex} since {tex}(A \cup B)'{/tex} Set represent the element which are not belongs to it,so there is no common element with the set A.So the answer is null set

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Let A = { 1,2,3,4} , B = { 2,3,4,5,6 } , then (A∩B)(A∩B)is equal to :

**A. ** { 1 }

**B. ** { 2,3,4 }

**C. ** { 5,6 }

**D. ** { 1,2,3 }

**Answer : ****Option B**

**Explaination / Solution: **

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Two sets A and B are said to be disjoint iff

**A. ** A ∪B = ϕ

**B. ** A – B = A

**C. ** A ∩B ≠ϕ

**D. ** A∩B=∅

**Answer : ****Option D**

**Explaination / Solution: **

Two sets are called disjoint if and only if these two set have no common element i.e A∩B=∅

Two sets are called disjoint if and only if these two set have no common element i.e A∩B=∅

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If A and B are two sets , then A∩(A∪B) is equal to

**A. ** A

**B. ** A ‘

**C. ** B

**D. ** none of these.

**Answer : ****Option A**

**Explaination / Solution: **

LetA={1,2,3,4}andB={1,2,3,4,5,6}HereA∪B={1,2,3,4,5,6}NowA∩(A∪B)={1,2,3,4,}=A

LetA={1,2,3,4}andB={1,2,3,4,5,6}HereA∪B={1,2,3,4,5,6}NowA∩(A∪B)={1,2,3,4,}=A

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If A = { 1,2,3 } , and B = { 1,3,5,7 } , then A∪B=

**A. ** none of these.

**B. ** { 1,2,3,5,7 }

**C. ** { 1,3,5,7 }

**D. ** { 1,2,3,7 }

**Answer : ****Option B**

**Explaination / Solution: **

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If n (A ) =3 and n ( B ) = 6 and A⊆ B , then n(A∩B) is equal to

**A. ** 6

**B. ** 3

**C. ** 0

**D. ** 9

**Answer : ****Option B**

**Explaination / Solution: **

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If aN = { ax : x ∈ N } , then the set 3N ∩ 7N is

**A. ** 21N

**B. ** 10N

**C. ** 7N

**D. ** 4N

**Answer : ****Option A**

**Explaination / Solution: **

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Which set is the subset of all given sets ?

**A. ** { }

**B. ** { 1,2,3,4 }

**C. ** { 1 }

**D. ** { 0 }

**Answer : ****Option A**

**Explaination / Solution: **

{ } denoted as null set. and Null set is subset of all sets.

{ } denoted as null set. and Null set is subset of all sets.

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If A⊂B , then

**A. ** Ac=Bc
**B. ** Ac⊂Bc
**C. ** Bc⊄Ac
**D. ** Bc⊂Ac
**Answer : ****Option D**

**Explaination / Solution: **

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Given the sets A = { 1, 2, 3 } , B = { 3 , 4 } , C = { 4 , 5, 6 } , then A ∪( B ∩ C ) is

**A. ** {1, 2, 3}

**B. ** { 1, 2 ,3 , 4, 5, 6 }

**C. ** { 1, 2 , 3 , 4 }

**D. ** { 3 }

**Answer : ****Option C**

**Explaination / Solution: **

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