The question below consists of a pair of related words followed by four pairs of words. Select the pair that best expresses the relation in the original pair:
Gladiator : Arena

**A. ** dancer : stage

**B. ** commuter: train

**C. ** teacher : classroom

**D. ** lawyer : courtroom

**Answer : ****Option A**

**Explaination / Solution: **

A gladiator performs in an arena. Commutators use trains. Lawyers performs, but do not entertain like a gladiator. Similarly, teachers educate. Only dancers performs on a stage.

A gladiator performs in an arena. Commutators use trains. Lawyers performs, but do not entertain like a gladiator. Similarly, teachers educate. Only dancers performs on a stage.

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The fuel consumed by a motorcycle during a journey while traveling at various
speeds is indicated in the graph below.

**A. ** P

**B. ** Q

**C. ** R

**D. ** S

**Answer : ****Option B**

**Explaination / Solution: **

Since fuel consumption/litre is asked and not total fuel consumed, only average speed is relevant. Maximum efficiency comes at 45 km/hr, So least fuel consumer per litre in lap Q

The distances covered during four laps of the journey are listed in the table below

From the given data, we can conclude that the fuel consumed per kilometre was
least during the lap

Since fuel consumption/litre is asked and not total fuel consumed, only average speed is relevant. Maximum efficiency comes at 45 km/hr, So least fuel consumer per litre in lap Q

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Two D flip-flops are connected as a synchronous counter that goes through the
following Q_{B}Q_{A }sequence 00⟶11⟶01⟶10⟶00⟶… The combination to the inputs DA and DB are

**A. **

**B. **

**C. **

**D. **

**Answer : ****Option D**

**Explaination / Solution: **

The sequence is QBQA

The sequence is QBQA

00⟶11⟶01⟶10⟶00⟶…

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Drift current in the semiconductors depends upon

**A. ** only the electric field

**B. ** only the carrier concentration gradient

**C. ** both the electric field and the carrier concentration

**D. ** both the electric field and the carrier concentration gradient

**Answer : ****Option C**

**Explaination / Solution: **

No Explaination.

No Explaination.

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For the BJT Q_{L} in the circuit shown below, The
switch is initially closed. At time t = 0, the switch is opened. The time t at
which Q_{1} leaves the active region is

**A. ** 10 ms

**B. ** 25 ms

**C. ** 50 ms

**D. ** 100 ms

**Answer : ****Option C**

**Explaination / Solution: **

Applying KCL at collector

with time, the capacitor charges and voltage across collector changes from 0
towards negative.

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A transmission line of characteristic impedance 50Ω is terminated by a 50 W load. When excited by a sinusoidal voltage source at 10 GHz, the phase difference between two points spaced 2 mm apart on the line is found to be π/4 radians. The phase velocity of the wave along the line is

**A. **
**B. **
**C. **
**D. **
**Answer : ****Option C**

**Explaination / Solution: **

We have d = 2 mm and f = 10 GHz

0.8 × 10^{8} m/s

1.2 × 10^{8} m/s

1.6 × 10^{8} m/s

3 × 10^{8} m/s

We have d = 2 mm and f = 10 GHz

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A message signal m(t) = cos 200πt + 4cosπt modulates the carrier
c(t) = coe 2πf_{c}t where f_{c} = 1MHz to produce an AM signal. For demodulating
the generated AM signal using an envelope detector, the time constant RC of
the detector circuit should satisfy

**A. ** 0.5 ms < RC < 1 ms

**B. ** 1 μs << RC < 0.5 ms

**C. ** RC << μs

**D. ** RC >> 0.5 ms

**Answer : ****Option B**

**Explaination / Solution: **

Highest frequency component in m(t) is

Highest frequency component in m(t) is

Carrier frequency fc = 1 MHz

For Envelope detector condition

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The root locus plot for a system is given below. The open loop transfer function
corresponding to this plot is given by

**A. **

**B. **

**C. **

**D. **

**Answer : ****Option B**

**Explaination / Solution: **

For given plot root locus exists from -3 to ∞, So there must be odd number of poles and zeros. There is a double pole at s = - 3

For given plot root locus exists from -3 to ∞, So there must be odd number of poles and zeros. There is a double pole at s = - 3

Now poles = 0, -2, -3, -3

zeros = - 1

Thus transfer function

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The input-output transfer function of a plant The plant is placed in a unity negative feedback configuration as shown in the figure below.

**A. **

**B. **

**C. **

**D. **

**Answer : ****Option D**

**Explaination / Solution: **

The signal flow graph that DOES NOT model the plant transfer function H(S) is

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Consider a closed surface S surrounding volume V. If is the position vector
of a point inside S, with the unit normal on S, the value of the integral is

**A. ** 3V

**B. ** 5V

**C. ** 10V

**D. ** 15V

**Answer : ****Option D**

**Explaination / Solution: **

From Divergence theorem, we have

From Divergence theorem, we have

The position vector

Here, , thus

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