Electric Circuits (Test 9)

Gate Exam : Ee Electrical Engineering

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Electric Circuits

Electric Circuits
| Electric Circuits |
Q.1
A source has an internal impedance of If a purely resistive load connected to this source has to extract the maximum power out of the source, its value inΩ should be
A. 3
B. 4
C. 5
D. 7
Answer : Option C
Explaination / Solution:

For the purely resistive load, maximum average power is transferred when

where
is the equivalent thevinin (input) impedance of the circuit. Hence,
 we obtain


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Q.2
If the 12 Ω resistor draws a current of 1A as shown in the figure, the value of resistance R is

A. 4Ω
B. 6Ω
C. 8Ω
D. 18Ω
Answer : Option B
Explaination / Solution:
No Explaination.


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Q.3
In the circuit shown below, the knee current of the ideal Zener diode is 10 mA. To maintain 5 V across RL, the minimum value of RL in Ω and the minimum power rating of the Zener diode in mW respectively are

A. 125 and 125
B. 125 and 250
C. 250 and 125
D. 250 and 250
Answer : Option B
Explaination / Solution:
No Explaination.


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Q.4
In the circuit shown below, the initial charge on the capacitor is 2.5 mC, with the voltage polarity as indicated. The switch is closed at time t = 0. The current i(t) at a time t after the switch is closed is

A. i(t) = 15 exp (-2 × 10t)A
B. i(t) = 5 exp (-2 × 10t)A
C. i(t) = 10 exp (-2 × 10t)A
D. i(t) = -5 exp (-2 × 10t)A
Answer : Option A
Explaination / Solution:

Here we take the current flow direction as positive.


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Q.5
The switch SW shown in the circuit is kept at position ‘1’ for a long duration. At t = 0+, the switch is moved to position ‘2’. Assuming |Vo2|Vo1|, the voltage  vc(t) across the capacitor is

A.
B.
C.
D.
Answer : Option D
Explaination / Solution:



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Q.6
The equivalent capacitance of the input loop of the circuit shown is

A. 2μ F
B. 200μ F
C. 100μ F
D. 4μFs
Answer : Option A
Explaination / Solution:
No Explaination.


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Q.7
In the following circuit, the input voltage Vin is 100 sin(100πt). For 100πRC = 50, the average voltages across R (in volts) under steady-state is nearest to

A. 100
B. 31.8
C. 200
D. 63.6
Answer : Option C
Explaination / Solution:

Given circuit is voltage doubler 
Vm = Voltage across each capacitor = 100V 
Voltage across two capacitors (in steady state) = 2Vm = 200V 

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Q.8
A voltage 1000 sin𝜔t Volts is applied across YZ . Assuming ideal diodes, the voltage measured across WX in Volts, is

A. sin𝜔t
B. (sin𝜔t + |sin𝜔t|)/2
C. (sin𝜔t - sin𝜔t/2
D. 0 for all t
Answer : Option D
Explaination / Solution:
No Explaination.


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EE Electrical Engineering