Electric Circuits (Test 7)

Gate Exam : Ee Electrical Engineering

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Electric Circuits

Electric Circuits
| Electric Circuits |
Q.1
For the two-port network shown below, the short-circuit admittance parameter matrix is

A.
B.
C.
D.
Answer : Option A
Explaination / Solution:

Given circuit is as shown below

By writing node equation at input port

By writing node equation at output port

From (1) and (2), we have admittance matrix


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Q.2
In the circuit shown below, the Norton equivalent current in amperes with respect to the terminals P and Q is

A. 6.4 - j 4.8
B. 6.56 - j 7.87
C. 10 + j0
D. 16 + j0
Answer : Option A
Explaination / Solution:

Replacing P - Q by short circuit as shown below we have
Using current divider rule the current ISC is



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Q.3
Three capacitors C1C2, and C3, whose values are 10µF, 5µF, and 2µF respectively, have breakdown voltages of 10V, 5V, and 2V respectively. For the interconnection shown, the maximum safe voltage in Volts that can be applied across the combination and the corresponding total charge in µC stored in the effective capacitance across the terminals are respectively

A. 2.8 and 36
B. 7 and 119
C. 2.8 and 32
D. 7 and 80
Answer : Option C
Explaination / Solution:
No Explaination.


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Q.4
The current I in the circuit shown is

A. -j1A
B. j1A
C. 0 A
D. 20 A
Answer : Option A
Explaination / Solution:



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Q.5
The L-C circuit shown in the figure has an inductance L = 1mH and a capacitance C = 10µF. 
The L – C circuit of Q.9 is used to commutate a thyristor. Which is initially carrying a current of 5 A as shown in the figure below. The values and initial conditions of L and C are the same as in Q.9. The switch is closed at t=0. If the forward drop is negligible, the time taken for the device to turn off is

A. 52 μs
B. 156 μs
C. 312 μs
D. 26 μs
Answer : Option A
Explaination / Solution:
No Explaination.


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Q.6
Assuming an ideal transformer,. The Thevenin’s equivalent voltage and impedance as seen from the terminals x and y for the circuit in figure are

A. 2sin(𝜔t), 4Ω
B. 1sin(𝜔t), 1Ω
C. 1sin(𝜔t), 2Ω
D. 2sin(𝜔t), 0.5Ω
Answer : Option A
Explaination / Solution:



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Q.7
The RC circuit shown in the figure is

A. a low-pass filter
B. a high-pass filter
C. a band-pass filter
D. a band-reject filter
Answer : Option C
Explaination / Solution:

At ω3, capacitor acts as short circuited and circuit acts as shown in fig below

At ω0, capacitor acts as open circuited and circuit look like as shown in fig below

So frequency response of the circuit is as shown in fig and circuit is a Band pass filter.


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Q.8
Two series resonant filters are as shown in the figure. Let the 3-dB bandwidth of Filter 1 be B1 and that of Filter 2 be B2. the value B1/Bis

A. 4
B. 1
C. 1/2
D. 1/4
Answer : Option D
Explaination / Solution:



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Q.9
In the ac network shown in the figure, the phasor voltage VA (in Volts) is

A. 0
B.
C.
D.
Answer : Option D
Explaination / Solution:



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EE Electrical Engineering