π = CRT
y = x (m)
m = RT
310 R = RT
∴ T = 310 K
= 37º C
π = CRT
π = [ W/MV ] . RT
M = WRT / π V
= [1.26 x 0.083x300] / [2.52x10-3x0.2]
= 62.22 Kg mol-1
Ba (OH)2 dissociates to form
Ba2+ and 2OH ion
α=(i-1) / (n-1)
i= α(n-1)+1
n=i=3 (for Ba(OH)2),
α =1)
10% W/W aqueous NaOH solution means that 10 g of sodium
hydroxide in 100g solution
Molality = no. of moles of solute / weight of solvent (in
kg)
= (10/40) / 0.1 =
0.25/0.1 = 2.5M
i = 0.54
α=(1-i)n/(n-1)
=(1-0.54)2 / (2-1)
α= 0.92
Reason : In an ideal solution, solvent-solvent as well as
solute-solute interactions are similar to solute-solvent interactions.