UNIT 9: Solutions - Online Test

Q1. The molality of a solution containing 1.8g of glucose dissolved in 250g of water is
Answer : Option D
Explaination / Solution:

molality = number of moles of solute / weight of solvent (in kg)

= (1.8/180) / 0.25 = 0.01/0.25 = 0.04M


Q2. Which of the following concentration terms is / are independent of temperature
Answer : Option D
Explaination / Solution:

Molality and mole fraction are independent of temperature.

Q3.

Stomach acid, a dilute solution of HCl can be neutralised by reaction with Aluminium hydroxide

Al (OH)3 + 3HCl (aq) → AlCl3 + 3 H2O

How many millilitres of 0.1 M Al(OH)3 solution are needed to neutralise 21 mL of 0.1 M HCl ?

Answer : Option B
Explaination / Solution:

M1 × V1 = M2 × V2                [ 0.1 M

Al(OH)3 gives 3 × 0.1 = 0.3 M OH– ions]

0.3 × V1 = 0.1 × 21

V1 = 01x21 / 0.3 = 7ml


Q4. The partial pressure of nitrogen in air is 0.76 atm and its Henry's law constant is 7.6 × 104 atm at 300K. What is the molefraction of nitrogen gas in the solution obtained when air is bubbled through water at 300K ?
Answer : Option D
Explaination / Solution:

PN2= 0.76 atm

KH = 7.6 × 104

x = ?

PN2 = KH . x

0.76 = 7.6 × 104 × x

so x = 0.76 / [7.6 x104] = 1x10-5


Q5. The Henry's law constant for the solubility of Nitrogen gas in water at 350 K is 8 × 104 atm. The mole fraction of nitrogen in air is 0.5. The number of moles of Nitrogen from air dissolved in 10 moles of water at 350K and 4 atm pressure is
Answer : Option D
Explaination / Solution:

KH = 8 × 104

(xN2)in air = 0.5

Total pressure = 4 atm

pressure Partial pressure of nitrogen = mole fraction × total pressure = 0.5 × 4 = 2



Q6. Which one of the following is incorrect for ideal solution ?
Answer : Option D
Explaination / Solution:

for an ideal solution,

ΔSmix ≠ 0 ; Hence ΔGmix ≠ 0

incorrect is ΔGmix = 0


Q7. Which one of the following gases has the lowest value of Henry's law constant ?
Answer : Option C
Explaination / Solution:

Carbon dioxide ; most stable gas and has lowest value of Henrys Law constant.

Q8. P1 and P2 are the vapour pressures of pure liquid components, 1 and 2 respectively of an ideal binary solution if x1 represents the mole fraction of component 1, the total pressure of the solution formed by 1 and 2 will be
Answer : Option C
Explaination / Solution:

Ptotal = P1 + P2

= P1x1 + P2x2           (x1 + x2 = 1)

= P1 (1 – x2) + P2x2    (x1 = 1 – x2)

= P1 – P1x2 + P2x2

= P1 – x2 (P1 – P2)


Q9. Osometic pressure (p) of a solution is given by the relation
Answer : Option B
Explaination / Solution:

π = CRT

π = n/V . RT

π V = nRT 


Q10. Which one of the following binary liquid mixtures exhibits positive deviation from Raoults law ?
Answer : Option D
Explaination / Solution:

Ethanol and water