Molar mass
= [ 2 x ( atomic mass of Al ) , 3 x ( atomic mass of O ) ]u
=
= ( 54 + 48 ) u
= 102 u.
Molar massof C6 H10 O5
= Sum of the atomic masses of six C atoms , ten H atoms & six O atoms
thus , substituting the required atomic masses of
C= 12 ,
H = 1 , &
O = 16 ,
we get ,
Molar mass of C6 H10 O5
= [ 6(12)+10(1)+5(16) ] u
= (72 + 10 + 80 ) u
=162 u
Molar mass of Ag NO3
= [ atomic mass of Ag + atomic mass of N + 3 ( atomic mass of O ) ) ] u
Substituting the atomic masses of Ag , N & O as 107.9 , 14 & 16 ,respectively in the above expression we get -
=
=169.9 u
How many atoms of Oxygen are there in 18g of water?
(Hint: Avagadro’s Number
= 6.02 x atoms/mol)
The problem is based upon the concepts of Avogadro's law
.Accordingly , one mole (ie 18 g ) of water contains
= 6.02 x molecules of water
. Again , since the number of oxygen atoms in one molecule of water ( H2 O )
= 1 atom
the number of oxygen atoms in 6.02 x 1023 molecules of water
.= 6.02 x 1023 atoms
Given that Avagadro’s Number
= 6.02 x 1023 atoms/mol ,
the number of hydrogen atoms in 18g of water is.
Since,18g H2O
= 1mol water containing 6.02 x 1023 molecules of water (H2O )
& the number of H atoms in 1 molecule of hydrogen (H2) = 2
the number of H atoms in 6.02 x 1023 molecules
= (6.02 x 1023 x 2)
=1.204 x 1024.
Since , 1 m
=1000 mm.
or, 1 mm
=
2000 mm
=[ ] m
= 2 m
Since , 1L
= 1000mL
or , 1mL
= .
0.05mL
=
= 0.00005 L .
Since , Molarity
=
substituting the given values , we get -
Molarity ( M )
=
=0.4M
* moles of solute ie. NaOH = mole
.= 0.1mol
Choose the most appropriate option to complete the statement -
" Whenever there is a rearrangement of atoms which makes or breaks chemical bonds ------------------------ "
Since ,as per Avogadro's law ,
the mass of 6.02 x molecules of
= 32 g
mass of 1 molecule of O2
=
= 5.32 x g