Q8.In how many ways can the word ENGINEER be arranged so that ‘G’ and ‘R’ are never together?
Answer : Option CExplaination / Solution:
Number of ways of rearranging the word ENGINEER = (8!)/(3!*2!) = 3360
Finding the number of ways of arranging the word ENGINEER such that G and R are always together is done by taking GR as a single alphabet and then finding the permutation.
Number of ways of arranging the word ENGINEER such that G and R are always together = (7!)/(3!*2!) = 420*2 = 840
∴Number of ways of arranging the word ENGINEER such that G and R are never together = Number of ways of rearranging the word ENGINEER - Number of ways of arranging the word ENGINEER such that G and R are always together
⇒Number of ways of arranging the word ENGINEER such that G and R are never together