Total ways of getting 2 and 4 exactly 3 times is 6! / (3! 3!) = 20
Total number of ways in throwing 6 dice is 66
Therefore probability is 20/ 66 = 5/11664
Total no. of outcomes = 6={2,2,2,6,6,6}
p(getting a six)=3/6=1/2
TOTAL NO. OF OUTCOMES=62=36
no. of outcomes in which both throws same no.={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6
p(both throws same no.)=6/36=1/6
Total number of ways of getting even number is 3
Out of these 3 even number we have to get either 2 or 4 which can be done in 2 ways.
So required probability is 2/3
on tossing a pair of dice total outcomes are 36
out of which getting a total of 8 have possiblities {(2,6),(6,2),(3,5),(5,3),(4,4)}=5
and from these 5 outcomes getting same no. on both dice is (4,4)=1
so, probability is 1/5