Probability - Online Test
Q1.
Two coins are tossed once ,where E :no tail appears , F : no head appers. Find P(E/F).
Answer : Option C
Explaination / Solution:
Q2. Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P (E|F) and P(F|E)
Answer : Option A
Explaination / Solution:
We have ,
P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, then ,
P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, then ,
Q3. Compute P(A|B), if P(B) = 0.5 and P (A ∩ B) = 0.32
Answer : Option A
Explaination / Solution:
We have , P(B) = 0.5 and P (A ∩ B) = 0.32
Q4. If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find P(A ∩ B)
Answer : Option A
Explaination / Solution:
We have ,
P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4
P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4
Q5. If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find P(A|B)
Answer : Option B
Explaination / Solution:
We have ,
P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4
P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4
Q6. If P (A) = 0.8, P (B) = 0.5 and P(B|A) = 0.4, find P(A ∪ B)
Answer : Option A
Explaination / Solution:
Q7. Evaluate P(A ∪ B), if 2P(A) = P(B) = and P(A|B) =
Answer : Option A
Explaination / Solution:
Q8. If P(A) = , P(B) = and P(A ∪ B) = find P(A|B)
Answer : Option B
Explaination / Solution:
Q9. Two dice are thrown. The number of sample points in the sample space when 6 does not appear on either dice is
Answer : Option C
Explaination / Solution:
total no. of outcomes=62=36
The pair which shows 6 on either dice are {(6,1),(6,2),(6,3),(6,4),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}=11
So total number of sample points in sample space when 6 on either dice do not appear=36-11=25
Q10. 8 coins are tossed at a time. The probability of getting 6 heads up is
Answer : Option B
Explaination / Solution:
Total ways of getting 6 heads out of 8 toss of coins is 28.
Total number of outcome is 28 = 256
Therefore probability is
