Oscillations - Online Test
Q1. What is constant in simple harmonic motion?
Answer : Option B
Explaination / Solution:
The time period of the SHM is given by where 'm' be the mass of the body (constant) , 'k' restoring force constant as T depends on 'm' and 'k' and they are constant for the system, so the corresponding Time period of the motion is Constant.
Q2. A particle of mass 10 g is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of seconds. The maximum value of the force acting on the particle is
Answer : Option A
Explaination / Solution:
Given , T= s
amplitude, x= 0.5 m
mass , m = 10g=0.01kg ,as we know that:
The maximum force is obtained at the maximum displacement i.e . amplitude
The negative value of force shows the attractive nature.
Q3. A body of mass 5 g is executing simple harmonic motion about a point O with amplitude of 10 cm. Its maximum velocity is 100 cm/s. It’s velocity will be 50 cm/s at a distance (in cm) from O
Answer : Option D
Explaination / Solution:
No Explaination.
Q4.
The maximum velocity and maximum acceleration of a body moving in a simple harmonic oscillation are 2 m/s and 4 . The angular velocity is
Answer : Option C
Explaination / Solution:
No Explaination.
Q5. A particle is executing simple harmonic motion with an amplitude of 0.02 meter and frequency 50 hertz. The maximum acceleration of the particle is
Answer : Option D
Explaination / Solution:
No Explaination.
Q6. The kinetic energy of a body executing S.H.M. is 1/3 of the potential energy. Then, the displacement of the body is x percent of the amplitude, where x is
Answer : Option D
Explaination / Solution:
No Explaination.
Q7. The total energy of a particle, executing simple harmonic motion is
Answer : Option B
Explaination / Solution:
(as)
Thus total energy of the oscillator remains constant as displacement is regained after every half cycle.
no energy is dissipated then all the potential energy becomes kinetic and vice versa.
Figure below shows the variation of kinetic energy and potential energy of harmonic oscillator with time where phase φ is set to zero for simplicity
Q8. A spring with spring constant k when stretched through 1 cm has a potential energy U. If it is stretched by 4 cm, the potential energy will become
Answer : Option A
Explaination / Solution:
No Explaination.
Q9. For a particle executing S.H.M having amplitude a, the speed of the particle is one-half of its maximum speed when its displacement from the mean position is
Answer : Option A
Explaination / Solution:
No Explaination.
Q10. The period of a spring oscillating simple harmonically is
Answer : Option D
Explaination / Solution:
No Explaination.
