(∼p∧∼q)∨(∼p∧q)
∼p∧(∼q∨q) distributive law
∼p∧T since ∼q∨q≡T
∼p since ∼p∧T≡∼p
p→(q∨r) = F
p→q=Fonly if p=Tand q=F
p=T and (q∨r)=F
qVr=F implies both q and r must be F.HenceT,F,F