Given 2(x−1)5≤3(2+x)7
Multiplying both sides by LCM(5,7)=35,we get
Solution set is [−44,∞)
What is the solution set for 0<−x2<3
0<−x2<3
Multiplying throughout by 2,we get
0<−x<6⇒0>x>−6
So solution set is ( - 6 , 0 )