let the point equidistant from the points ( 0 , 0 , 0 ) , ( 1 , 0 , 0 ) , ( 0 , 2 , 0 ) , and ( 0 , 0 , 3 ) is (x ,y ,z)
then according to the given condition and distance formula between two points we have
taking ist two expressions and solving them we get
Similarly by taking ist and 3rd we get y = 1 and by taking ist and 4th we get z = 3/2
So the required point is ( 1/2 , 1 , 3/2 )
Let P() be the point and Q (0,b,0) be any point on Y axis.
drs of PQ=(
drs of y axis (0,b,0)
Since PQ perpendicular to y axis.hence a1a2+b1b2+c1c2=0
hence the foot of perpendicular will be