x(x2−1)dx=dy∫(x3−x)dx=∫dyx44−x22=y+c
Here y =0 when x =2
244−222=0+c4−2=c∴c=2
Hence x44−x22=y+2
For the differential equationxydydx=(x+2)(y+2)find the solution curve passing through the point (1, –1).