Let a resistance M be put in parallel to S and the equivalent resistance of the parallel combination be X. In the bridge balance condition
In the parallel combination of S and M,
The current Ig through a galvanometer of resistance G is 0.02 I where I is the main current.
The shunt resistance S is calculated as follows.
An ideal voltmeter does not draw any current. Therefore the resistances 4000 Ω and 3000 Ω are in series. The current in the circuit
The potential difference across the 3000 Ω resistor