Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

**A. ** 648

**B. ** 1800

**C. ** 2700

**D. ** 10800

**Answer : ****Option B**

**Explaination / Solution: **

Let the required number of bottles be *x*.

*More machines, More bottles (Direct Proportion)*

*More minutes, More bottles (Direct Proportion)*

Machines | 6 | : | 10 | :: 270 : x | |

Time (in minutes) | 1 | : | 4 |

6 x 1 x *x* = 10 x 4 x 270

x = | (10 x 4 x 270) |

(6) |

*x* = 1800.

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A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.

**A. ** 2 hours

**B. ** 3 hours

**C. ** 4 hours

**D. ** 5 hours

**Answer : ****Option C**

**Explaination / Solution: **

Speed downstream = (13 + 4) km/hr = 17 km/hr.

Time taken to travel 68 km downstream = | 68 | hrs = 4 hrs. | |

17 |

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A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:

**A. ** 8.5 km/hr

**B. ** 9 km/hr

**C. ** 10 km/hr

**D. ** 12.5 km/hr

**Answer : ****Option C**

**Explaination / Solution: **

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.

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Which of the following statements is not correct?

**A. ** log_{10} 10 = 1

**B. ** log (2 + 3) = log (2 x 3)

**C. ** log_{10} 1 = 0

**D. ** log (1 + 2 + 3) = log 1 + log 2 + log 3

**Answer : ****Option B**

**Explaination / Solution: **

(a) Since log_{a} *a* = 1, so log_{10} 10 = 1.

(b) log (2 + 3) = log 5 and log (2 x 3) = log 6 = log 2 + log 3

log (2 + 3) log (2 x 3)

(c) Since log_{a} 1 = 0, so log_{10} 1 = 0.

(d) log (1 + 2 + 3) = log 6 = log (1 x 2 x 3) = log 1 + log 2 + log 3.

So, (b) is incorrect.

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If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:

**A. ** 2.870

**B. ** 2.967

**C. ** 3.876

**D. ** 3.912

**Answer : ****Option C**

**Explaination / Solution: **

log_{5} 512 |
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= 3.876 |

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In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:

**A. ** Rs. 3100

**B. ** Rs. 6240

**C. ** Rs. 6500

**D. ** Rs. 9600

**Answer : ****Option B**

**Explaination / Solution: **

To obtain Rs. 10, investment = Rs. 96.

To obtain Rs. 650, investment = Rs. | 96 | x 650 | = Rs. 6240. | ||

10 |

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A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:

**A. ** Rs. 12

**B. ** Rs. 15

**C. ** Rs. 18

**D. ** Rs. 21

**Answer : ****Option B**

**Explaination / Solution: **

Dividend on Rs. 20 = Rs. | 9 | x 20 | = Rs. | 9 | . | ||

100 | 5 |

Rs. 12 is an income on Rs. 100.

Rs. | 9 | is an income on Rs. | 100 | x | 9 | = Rs. 15. | ||

5 | 12 | 5 |

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A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:

**A. ** 0%

**B. ** 5%

**C. ** 7.5%

**D. ** 10%

**Answer : ****Option A**

**Explaination / Solution: **

C.P. = Rs. 3000.

S.P. = Rs. | 3600 x 100 | = Rs. 3000. | ||

100 + (10 x 2) |

Gain = 0%.

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A trader owes a merchant Rs. 10,028 due 1 year hence. The trader wants to settle the account after 3 months. If the rate of interest 12% per annum, how much cash should he pay?

**A. ** Rs. 9025.20

**B. ** Rs. 9200

**C. ** Rs. 9600

**D. ** Rs. 9560

**Answer : ****Option B**

**Explaination / Solution: **

Required money | = P.W. of Rs. 10028 due 9 months hence | |||||||||||

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= Rs. 9200. |

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Which one of the following is not a prime number?

**A. ** 31

**B. ** 61

**C. ** 71

**D. ** 91

**Answer : ****Option D**

**Explaination / Solution: **

91 is divisible by 7. So, it is not a prime number.

91 is divisible by 7. So, it is not a prime number.

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