Aldehydes Ketones and Carboxylic Acids - Online Test
Q1. In Hell – Volhard Zelinsky reaction, halogen reacts with
Answer : Option B
Explaination / Solution:
Alpha Hydrogen containing carboxylic acids undergo HVZ reaction.
Q2. In Hell – Volhard Zelinsky reaction, the reagents used are
Answer : Option C
Explaination / Solution:
In HVZ we use X2 in presence of Red P4 .
Q3.
Compound 'A' undergoes formation of cyanohydrins which on hydrolysis gives lactic acid (CH3 CHOHCOOH). Therefore, compound 'A' is
Answer : Option A
Explaination / Solution:
And on hydrolysis CN converts to COOH.
And on hydrolysis CN converts to COOH.
Q4. Which sequence of steps below describes the best synthesis of 5 – oxohexanoic acid starting with 1 – methylcyclopentan – 1 – ol
Answer : Option B
Explaination / Solution:
5 – oxohexanoic acid starting with 1 – methylcyclopentan – 1 – ol can be synthesized using conc H2SO4 which will cause dehydration forming alkene which with KMnO4 opens the ring and forms 1 – methylcyclopentan – 1 – ol.
Q5. The compound which forms acetaldehyde when heated with dilute NaOH is
Answer : Option D
Explaination / Solution:
Q6. For making distinction between 2 – pentanone and 3 – pentanone the reagent to be employed is
Answer : Option D
Explaination / Solution:
2-pentanone will give iodoform but 3-pentanone will not give.
Q7. A strong base can abstract an α – hydrogen from
Answer : Option A
Explaination / Solution:
Because conjugate base that form will be stable in case of Ketone.
Q8. The product formed in Aldol condensation is
Answer : Option C
Explaination / Solution:
In aldol we get beta hydroxyl aldehyde/Ketone.
Q9. Which of the following reagents can be used to convert a carboxylic acid directly into its corresponding acid chloride derivative?
Answer : Option B
Explaination / Solution:
Q10. What compound is produced when cyclohexene is treated with concentrated KMnO4?
Answer : Option C
Explaination / Solution:
Conc KMnO4 will cause oxidation and ring opening forming adipic acid.
