T1 = 25 + 273 = 298 K
T2 = 700 K
ΔHº is –ve ie., forward reaction is exothermic
Stomach acid, a dilute solution of HCl can be neutralised by
reaction with Aluminium hydroxide
Al (OH)3 + 3HCl (aq) → AlCl3 + 3 H2O
How many millilitres of 0.1 M Al(OH)3 solution are needed to
neutralise 21 mL of 0.1 M HCl ?
M1 × V1 = M2 × V2 [∵ 0.1 M
Al(OH)3 gives 3 × 0.1 = 0.3 M OH– ions]
0.3 × V1 = 0.1 × 21
V1 = 01x21 / 0.3 = 7ml
- electron rich,
CH3 – CH3 – Covalent neutral molecule.
BH3 - electron deficient
Spliting of spectral lines in magnetic field is
called Zeeman effect and spliting of spectral lines in electric field, is
called Stark effect.