ME GATE 2013 - Online Test
Q1. In a CAD package, mirror image of a 2D point P(5, 10) is to be obtained about a
line which passes through the origin and makes an angle of 45° counterlockwise
with the X-axis. The coordinates of the transformed point will be
Answer : Option B
Explaination / Solution:
No Explaination.
Q2. A bar is subjected to fluctuating tensile load from 20 kN to 100 kN. The material
has yield strength of 240 MPa and endurance limit in reversed bending is 160
MPa. According to the Soderberg principle, the area of cross-section in mm2 of
the bar for a factor of safety of 2 is
Answer : Option D
Explaination / Solution:
Q3. A simply supported beam of length L is subjected to a varying distributed load 
where the distance x is measured from the left support. The
magnitude of the vertical force in N at the left support is
where the distance x is measured from the left support. The
magnitude of the vertical force in N at the left support is
Answer : Option B
Explaination / Solution:
Since the load is distributed equally on both supports
Q4. A single riveted lap joint of two similar plates as shown in the figure below has
the following geometrical and material details: 
Width of the plate w=200 mm, thickness of the plate t=5 mm, number of rivets
n=3, diameter of the rivet dr = 10mm, diameter of the rivet hole dh = 11mm, allowable tensile stress of the plate σp = 200 MPa, allowable shear stress of the
rivet σs = 100 MPa and allowable bearing stress of the σc = 150 MPa
If the rivets are to be designed to avoid crushing failure, the maximum
permissible load P in kN is
Answer : Option C
Explaination / Solution:
No Explaination.
Q5. A single riveted lap joint of two similar plates as shown in the figure below has the following geometrical and material details:
Width of the plate w=200 mm, thickness of the plate t=5 mm, number of rivets n=3, diameter of the rivet dr = 10mm, diameter of the rivet hole dh = 11mm, allowable tensile stress of the plate σp = 200 MPa, allowable shear stress of the rivet σs = 100 MPa and allowable bearing stress of the σc = 150 MPa
If the plates are to be designed to avoid tearing failure, the maximum
permissible load P in kN is
Answer : Option C
Explaination / Solution:
No Explaination.
Q6. In orthogonal turning of a bar of 100 mm diameter with a feed of 0.25 mm/rev,
depth of cut of 4 mm and cutting velocity of 90 m/min, it is observed that the
main (tangential) cutting force is perpendicular to the friction force acting at the
chip-tool interface. The main (tangential) cutting force is 1500 N.
The orthogonal rake angle of the cutting tool in degree is
Answer : Option A
Explaination / Solution:
No Explaination.
Q7. A rod of length L having uniform cross-sectional area A is subjected to a tensile
force P as shown in the figure below. If the Young’s modulus of the material
varies linearly from E1 to E2 along the length of the rod, the normal stress
developed at the section-SS is
Answer : Option A
Explaination / Solution:
Stress depends on area.
Q8. Customers arrive at a ticket counter at a rate of 50 per hour and tickets are issued in the order of their arrival. The average time taken for issuing a ticket is 1min. Assuming that customer arrivals form a Poisson process and service times are exponentially distributed, the average waiting time in queue in minutes is:
Answer : Option C
Explaination / Solution:
Q9. What will be the maximum sum of 44, 42, 40, ... ?
Answer : Option C
Explaination / Solution:
The maximum sum is the sum of 44, 42,- - - - -2.
The sum of ‘n’ terms of an AP
= n/2[2a + (n-1)d]
In this case, n = 22, a = 2 and d = 2
Sum = 11[4+21×2] = 11×46 = 506
Q10. Out of all the 2-digit integers between 1 and 100, a 2-digit number has to be
selected at random. What is the probability that the selected number is not
divisible by 7?
Answer : Option D
Explaination / Solution:
The number of 2 digit multiples of 7 = 13
Probability of choosing a number
Not divisible by 7 = (90-13)/90 = 77/90
