A system described by a linear, constant coefficient, ordinary, first order
differential equation has an exact solution given by y(t) for t > 0, when the
forcing function is x(t) and the initial condition is y(0). If one wishes to modify
the system so that the solution becomes -2y(t) for t > 0, we need to

**A. ** change the initial condition to -y(t) and the forcing function to 2x(t)

**B. ** change the initial condition to 2y(0) and the forcing function to -x(t)

**C. ** change the initial condition to j√2y(0) and the forcing function to j√2x(t)

**D. ** change the initial condition to -2y(0) and the forcing function to -2x(t)

**Answer : ****Option D**

**Explaination / Solution: **

No Explaination.

No Explaination.

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Consider two identically distributed zero-mean random variables U and V. Let the cumulative distribution functions of U and 2V be F(x) and G(x) respectively. Then, for all values of x

**A. ** F(x) - G(x) ≤ 0

**B. ** F(x) - G(x) ≥ 0

**C. ** (F(x) - G(x)).x ≤ 0

**D. ** (F(x) - G(x)).x ≥ 0

**Answer : ****Option C**

**Explaination / Solution: **

No Explaination.

No Explaination.

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