For the two-port network shown below, the short-circuit admittance parameter matrix is

Given circuit is as shown below

By writing node equation at input port

By writing node equation at output port

From (1) and (2), we have admittance matrix

Workspace

Report

For parallel RLC circuit, which one of the following statements is NOT correct ?

**A. ** The bandwidth of the circuit decreases if R is increased

**B. ** The bandwidth of the circuit remains same if L is increased

**C. ** At resonance, input impedance is a real quantity

**D. ** At resonance, the magnitude of input impedance attains its minimum values.

**Answer : ****Option D**

**Explaination / Solution: **

A parallel RLC circuit is shown below :

A parallel RLC circuit is shown below :

Input impedance

Workspace

Report

In the circuit shown, the switch S is open for a long time and is closed at t = 0. The current i (t) for t ≥ 0^{+}is

When the switch S is open for a long time before t < 0, the circuit is

At t = 0, inductor current does not change simultaneously, So the circuit is

Current is resistor (AB)

i(0) = 0.75/2 = 0.375 A

Similarly for steady state the circuit is as shown below

B = 0.375 - 0.5 =- 0.125

Workspace

Report

The current I in the circuit shown is

**A. ** -j1A

**B. ** j1A

**C. ** 0 A

**D. ** 20 A

**Answer : ****Option A**

**Explaination / Solution: **

Workspace

Report

In the circuit shown, the power supplied by the voltage source is

**A. ** 0 W

**B. ** 5 W

**C. ** 10 W

**D. ** 100 W

**Answer : ****Option A**

**Explaination / Solution: **

Applying nodal analysis

Applying nodal analysis

Current from voltage source is

Since current through voltage source is zero, therefore power delivered is zero.

Workspace

Report

The eigen values of a skew-symmetric matrix are

**A. ** always zero

**B. ** always pure imaginary

**C. ** either zero or pure imaginary

**D. ** always real

**Answer : ****Option C**

**Explaination / Solution: **

Eigen value of a Skew-symmetric matrix are either zero or pure imaginary in conjugate pairs.

Eigen value of a Skew-symmetric matrix are either zero or pure imaginary in conjugate pairs.

Workspace

Report

The trigonometric Fourier series for the waveform f (t) shown below contains

**A. ** only cosine terms and zero values for the dc components

**B. ** only cosine terms and a positive value for the dc components

**C. ** only cosine terms and a negative value for the dc components

**D. ** only sine terms and a negative value for the dc components

**Answer : ****Option C**

**Explaination / Solution: **

For a function x(t) trigonometric fourier series is

For a function x(t) trigonometric fourier series is

For an even function x(t),B^{n} = 0

Since given function is even function so coefficient B^{n} = 0, only cosine and constant

terms are present in its fourier series representation.

Constant term :

Constant term is negative.

Workspace

Report

A function n(x) satisfied the differential equation where L is a constant. The boundary conditions are :n(0) = K and n(∞) = 0. The solution to this equation is
**A. ** n(x) = Kexp(x/L)

**B. ** n(x) = Kexp(- x/ √L)

**C. ** n(x) = K^{2} exp(- x/L)

**D. ** n(x) = Kexp(- x/L)

**Answer : ****Option D**

**Explaination / Solution: **

Given differential equation

Given differential equation

Workspace

Report

Consider the z -transform The inverse z -transform x[n] is
**A. ** 5𝛿[n + 2] + 3𝛿[n] + 4𝛿[n - 1]

**B. ** 5𝛿[n - 2] + 3𝛿[n] + 4𝛿[n + 1]

**C. ** 5u[n + 2] + 3u[n] + 4u[n - 1]

**D. ** 5u[n - 2] + 3u[n] + 4u[n + 1]

**Answer : ****Option A**

**Explaination / Solution: **

Workspace

Report

If e^{y} = x^{1/x} , then y has a

**A. ** maximum at x = e

**B. ** minimum at x = e

**C. ** maximum at x = e^{-1}

**D. ** minimum at x = e^{-1}

**Answer : ****Option A**

**Explaination / Solution: **

Workspace

Report