CE GATE 2013 - Online Test
Q1. The pair that best express a relationship similar to that expression in the pair:
Medicine: Health
Answer : Option C
Explaination / Solution:
Medicine leads to good health. Similarly, Education leads to Knowledge. Science
does not lead to experiment. Wealth may not necessarily lead to peace. Also
money may not also lead to happiness all the time
Q2. The normal depth in a wide rectangular channel is increased by 10%. The
percentage increase in discharge in the channel is
Answer : Option D
Explaination / Solution:
The discharge in the channel is given by
Q3. Which of the following options is closest in meaning to the word given below?
“Primeval”
Answer : Option C
Explaination / Solution:
Primeval pertains to the first age or ages, especially of the world. E.g.: primeval
forms of life
Q4. A 2 km pipe of 0.2 m diameter connects two reservoirs. The difference between
the water levels in the reservoir is 8 m. The Darcy Weisbach friction factor of the
pipe is 0.04. Accounting for frictional entry and exit losses, the velocity in the
pipe in (m/sec) is
Answer : Option A
Explaination / Solution:
Q5. A settling tank is designed for a surface overflow rate of 
Assuming
specific gravity of sediment particles = 2.65, Density of water, rw = 1000 kg / m3, dynamic viscosity of water mwater = 0.001 Ns / m2 and stokes law is valid.
The approximate minimum size of particles which can be completely removed is
Assuming
specific gravity of sediment particles = 2.65, Density of water, rw = 1000 kg / m3, dynamic viscosity of water mwater = 0.001 Ns / m2 and stokes law is valid.
The approximate minimum size of particles which can be completely removed is
Answer : Option B
Explaination / Solution:
To calculate minimum size of particles equating settling velocity to overflow rate,
we get
Q6. The transplantation of rice requires 10 days and total depth of water required
during transplantation is 48 cm. During transplantation there is an effective
rainfall (useful for irrigation) of 8 cm. The duty of irrigation water in hectare/
cumecs is
Answer : Option B
Explaination / Solution:
D = 864B / ∆ hectares / cumecs = (864×10)/((48-8)×10) = 216 hectares / cumecs
Q7. A multistorey building with a basement is to be constructed. The top 4 m
contains loose silt below which dense sand layer is present upto a great depth.
Ground water table is at the ground surface. The foundation consists of the
basement slab of 6 m width which will rest on the top of dense sand as shown in
figure. For dense sand saturated unit weight is 3 20kN / m3 and bearing
capacity factor, Nq = 40, Nγ = 45, for loose silt saturated unit
weight = 18kN / m3 , Nq = 15, Nγ = 20 . Effective cohesion is 0. Neglect depth factor
average elastic modulus E, and Poisson ratio µ of dense sand is 60 ×102 kN / m2 and 0.3 respectively, using factor of safety = 3. (Take influence
factor = 2)
The net safe bearing capacity (in kN / m3) of foundation is
Answer : Option C
Explaination / Solution:
Q8. Creep strain is
Answer : Option A
Explaination / Solution:
No Explaination.
Q9. Select the strength parameter of concrete used in design of plain jointed cement
pavement from the following choices:
Answer : Option C
Explaination / Solution:
No Explaination.
Q10. Four columns of building are to be located within a plot size of 10m ×10m . The
expected load on each column is 400 kN. Allowable bearing capacity of soil
deposit is 2 100kN / m2 . The type of foundation to be used is
Answer : Option A
Explaination / Solution:
Load on each column = 400kN
Bearing capacity of soil = 100 kN/m2
Area of each footing required = 400/100m2 = 4m2
Total area required = 4×4 = 16m2
Foundation area/Plot area = 16/100 = 16%
If the foundation area is less than 40% of plot area, then isolated foundation is
suitable.
