CE GATE 2013 - Online Test
Q1. For two major-roads with divided carriage way crossing at right angle, a full
clover leaf interchange with four indirect ramps is provided. Following statements
are made on turning movement of vehicles to all direction from both roads.
Identity the correct statement
Answer : Option B
Explaination / Solution:
No Explaination.
Q2. Match the given water properties in Group-I to the given titrants shown in
Group-II
Answer : Option C
Explaination / Solution:
No Explaination.
Q3. A 1 hour rainfall of 10 cm has return period of 50 year. The probability that
1 hour of rainfall 10 cm or more will occur in each of two successive years is
Answer : Option D
Explaination / Solution:
Return period of rainfall, T = 50 years
Probability of occurrence once in 50 years, p = 1/50 = 0.02
Probability of occurrence in each of 2 successive years = p2 = (0.02)2 = 0.0004
Q4. The latitude and departure of a line AB are +78m and −45.1m respectively. The
whole circle bearing of the line AB is
Answer : Option D
Explaination / Solution:
Since the latitude of line is positive and departure is negative, the line lies in
Fourth quadrant.
l cos θ = 78; l sin θ = -45.1
tanθ = -0.578
θ = -30o
WCB of AB = 360o-30o = 330o
Q5. An isohyet is a line joining points of
Answer : Option C
Explaination / Solution:
No Explaination.
Q6. As per IS 800: 2007 the cross-section in which extreme fibre can reach the yield
stress but cannot develop the plastic moment of resistance due to local buckling
is classified as
Answer : Option C
Explaination / Solution:
As per clause 3.7.2 of IS 800:2007
Q7. In compacted cylindrical bituminous mix, VMA = 15%(void mineral aggregate); Vv = 4.5% (air void) The magnitude of VFB (void filled bituminous) is
Answer : Option D
Explaination / Solution:
VFB = VB/Vv = ((15-4.5)/15)×100% = 70%
Q8. Following statement are made on compacted soil, where DS stands for soil
compaction on Dry Side of OMC and WS stands for soil compacted on Wet Side of
OMC. Identify incorrect statement
Answer : Option C
Explaination / Solution:
No Explaination.
Q9. Elevation and temperature data for places are tabulated below
Based on this data, lapse rate can be referred as
Answer : Option A
Explaination / Solution:
Ambient lapse rate = ((21.25 - 15.70)/(444 - 4))×1000 = 12.6 oC/km[>9.8 oC/km]
When the ambient lapse rate exceeds the adiabatic lapse rate, the ambient lapse
rate is said to be super adiabatic.
Q10. Bearing of the given system is shown below:
Applying correction due to local attraction, the correct bearing of line BC will be
Answer : Option D
Explaination / Solution:
The difference between back bearing and fore bearing of line DE
= 258o 30' -78o 30' = 180o
∴ Station D and E are free from local attraction
Fore bearing of line o EA = 212o 30'
∴Correct back bearing of line EA = 216o 30' - 180o = 36o 30'
Error at A = 31o 45' - 36o 30' = -4o 45'; Hence correction at A = +4o 45'
Correct fore bearing of line AB = 126o 45' + 4o 45' = 131o 30'
Correct back bearing of AB = 131o 30 + 180o = 311o 30'
Error at B = -3o 30'; Correction at B = +3o 30'
Hence correct bearing of BC = 45o 15' + 3o 30' = 48o 45'
