Direction: what will come in the place question mark in question given below?

**A. ** 25

**B. ** 28

**C. ** 30

**D. ** 26

**E. ** None of these

**Answer : ****Option D**

**Explaination / Solution: **

Series Pattern is+4, So next series 22+4 = 26

10, 14, 18, 22, ?

Series Pattern is+4, So next series 22+4 = 26

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Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If two stones are picked at random, what is the probability that both are blue?

Probability if both is blue

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Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If four balls are picked at random, what is the probability that two are blue and two are red?

Probability if two are Blue and two are Red

[(^{4}C_{2}*^{5}C_{2})/^{12}C_{4}] = (6*10)/495 → 4/33

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Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If three balls are picked at random, what is the probability that at least one is green?

Probability if at least one is Green

[1-(^{9}C_{3}/^{12}C_{3})] = 84/220 → 34/55

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Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If two balls are picked at random, what is the probability that either both are red or both are blue?

Probabilities if both either are Red or either are blue

= (^{5}C_{2} + ^{4}C_{2})/^{12}C_{2} = (10+6)/66 → 8/33

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Direction: Study the given information carefully and answer the questions that follow:

A basket contains 5 red, 4 blue, 3 green stones.

If four balls are picked at random, what is the probability that two are blue, one is green and one is red?

Probabilities if two are blue and one is green and one is red

= [(^{4}C_{2}*^{3}C_{1}*^{5}C_{1})/ ^{12}C_{4}] = (6*3*5)/(495) = 2/11

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Direction: Study the given information carefully and answer the questions that follow—

A store contains 4 red, 5 blue, 4 green shirts.

If two shirts are picked at random, what is the probability that both are green?

Probabilities if both are green

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If three shirts are picked at random, what is the probability that two are blue and one is red?

**A. ** 21/143

**B. ** 20/113

**C. ** 20/143

**D. ** 13/113

**E. ** None of these

**Answer : ****Option C**

**Explaination / Solution: **

Probability if two are Blue and one are Red

[(^{5}C_{2}*^{4}C_{1})/^{13}C_{3}] = (10*4)/286 → 20/143

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If two shirts are picked at random, what is the probability that at least one is green?

**A. ** 11/23

**B. ** 7/13

**C. ** 5/17

**D. ** 4/11

**E. ** None of these

**Answer : ****Option B**

**Explaination / Solution: **

Probability if at least one is Green

[1-(^{9}C_{2}/^{13}C_{2})] = 42/78 → 7/13

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If two shirts are picked at random, what is the probability that either both are red or both are green?

**A. ** 2/13

**B. ** 1/13

**C. ** 9/13

**D. ** 7/26

**E. ** None of these

**Answer : ****Option A**

**Explaination / Solution: **

Probabilities if both either are Red or either are green

(^{4}C_{2} + ^{4}C_{2})/^{13}C_{2} = (6+6)/78 → 2/13

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