# Algebra (Test 5)

## Problem Solving And Reasoning : Mathematics Or Quantitative Aptitude

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Algebra
| Algebra |
Q.1
If  then
A. p=q=r
B. p+q+r=0
C. p+r=q
D. p=q+r
Explaination / Solution:

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Q.2
If x = 11 then  - 12x4+ 13- 12 + 12x – 5 = ?
A. 1330
B. 1335
C. 1337
D. 1332
Explaination / Solution:

x– 12x4 + 13x3 + 12x2 + 12x – 5
x5 - 12x4 + 12x3 - 12x2 + 12x – 5 + x3
x5 - 11x4 - x4 + 11x3 + x3 - 11x2 - x2 + 11x + x – 5 + x3
x4 (x-11) - x3 (x-11) + x2 (x-11) – x (x-11) + x-5 + x3
= 11- 5 + (11)3
= 1331 + 6 = 1337

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Q.3
if a + b + c=0 then the value of
is
A. 0
B. 1
C. 3
D. 2
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Q.4
and , the value of is
A. 3/4
B. 4/3
C. 3/5
D. 5/3
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Q.5
if , then the value of  equals
A. 90
B. 100
C. 110
D. 120
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Q.6
The value of x which satisfies the equation

A. (a2 + b2 + c2)
B. -(a2 + b2 + c2)
C. (a2 + 2b2 + c2)
D. -(a2 + b2 + 2c2)
Explaination / Solution:

Of the given option,

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Q.7
If a, b, c are three non-zero real numbers such that a + b + c = 0, and b2ca, then the value of s
A. 3
B. 2
C. 0
D. 1
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Q.8
Ifthen the value of
A. 4
B. 52
C. 64
D. 76
Explaination / Solution:

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Q.9
If a = 25, b = 15, c = –10, then the value ofis
A. 30
B. -15
C. -30
D. 15
Explaination / Solution:

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Q.10
If  +  +  = 1 then  +  +  = ?
A. 1009
B. 1
C. 0
D. 2
Explaination / Solution:

+  +  = 1
Let = P = 2
Q = 4
Z = 2018
Then    +  +  =  (2/3) + (4/6) + 2018/(2018+1009)
(2/3) + (2/3) + (2/3) = 2

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