In which one of the following page replacement policies, Belady’s anomaly may occur?

**A. ** FIFO

**B. ** Optimal

**C. ** LRU

**D. ** MRU

**Answer : ****Option A**

**Explaination / Solution: **

No Explaination.

No Explaination.

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Consider the basic block given below.

**A. ** 6 and 6

**B. ** 8 and 10

**C. ** 9 and 12

**D. ** 4 and 4

**Answer : ****Option A**

**Explaination / Solution: **

The given basic block can be rewritten as

a = b + c

c = a + d

d = b + c

e = d - b

a = e + b

The minimum number of nodes and edges present in the DAG representation of the above
basic block respectively are

The given basic block can be rewritten as

From above simplification it is visible that e is same as c and final value of a is same as d. So
the final basic block can be written as follows:

The DAG generated for the above basic block in as

Maximum number of modes and edges in above DAG is (6,6)

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The following key values are inserted into a B+-tree in which order of the internal nodes is 3, and that
of the leaf nodes is 2, in the sequence given below. The order of internal nodes is the maximum number
of tree pointers in each node, and the order of leaf nodes is the maximum number of data items that
can be stored in it. The B+-tree is initially empty. 10, 3, 6, 8, 4, 2, 1. The maximum number of times leaf
nodes would get split up as a result of these insertions is

**A. ** 2

**B. ** 3

**C. ** 4

**D. ** 5

**Answer : ****Option C**

**Explaination / Solution: **

No Explaination.

No Explaination.

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Let G=(V, E) be a graph. Define where i_{d} is the number of
vertices of degree d in G. If S and T are two different trees with ξ(S) = ξ(T), then

**A. ** |S| = 2|T|

**B. ** |S| = |T| - 1

**C. ** |S| = |T|

**D. ** |S| = |T| + 1

**Answer : ****Option D**

**Explaination / Solution: **

No Explaination.

No Explaination.

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Consider two decision problems Q_{1}, Q_{2} such that Q_{1} reduces in polynomial time to 3-SAT
and 3 -SAT reduces in polynomial time to Q_{2}. Then which one of following is consistent with
the above statement?

**A. ** Q_{1} is in NP, Q_{2} in NP hard

**B. ** Q_{2} is in NP, Q_{1} is NP hard

**C. ** Both Q_{1} and Q_{2} are in NP

**D. ** Both Q_{1} and Q_{2} are NP hard

**Answer : ****Option A**

**Explaination / Solution: **

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Consider the following routing table at an IP router:

**A. ** i - a, ii - c, iii - e, iv - d

**B. ** i - a, ii - d, iii - b, iv - e

**C. ** i - b, ii - c, iii - d, iv - e

**D. ** i - b, ii - c, iii - e, iv - d

**Answer : ****Option A**

**Explaination / Solution: **

No Explaination.

For each IP address in Group I identify the correct choice of the next hop from Group II using
the entries from the routing table above.

No Explaination.

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The following is comment written for a C function

/* This function computes the roots of a quadratic equation

a.x^2+b.x+c=0. The function stores two real roots

in *root1 and *root2 and returns the status of validity of

roots. It handles four different kinds of cases.

(i) When coefficient a is zero irrespective of discriminant

(ii) When discriminant is positive

(iii) When discrimanant is zero

(iv) When discrimanant is negative

Only in cases (ii) and (iii), the stored roots are valid.

Otherwise 0 is stored in the roots. the function returns 0 when

the roots are valid and -1 otherwise.

The functin also ensures root1>=root2.

int get_QuadRoots (float a, float b, float c, float *root1, float *root2) ;

*/

A software test engineer is assigned the job of doing black box testing. He comes
up with the following test cases, many of which are redundant.

Which one of the following options provide the set of non-redundant tests using
equivalence class partitioning approach from input perspective for black box
testing?

T

T_{3}, T_{4}: in both case discriminant (D)= b^{2} − 4ac = 0 . Hence any one of it is
redundant.

T_{5} : D>0

T_{6} : D<0

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Let G be a weighted connected undirected graph with distinct positive edge weights. If every edge weight is increased by the same value, then which of the following statements is/are TRUE?
P: Minimum spanning tree of G does not change Q: Shortest path between any pair of vertices does not change

**A. ** P only

**B. ** Q only

**C. ** Neither P nor Q

**D. ** Both P and Q

**Answer : ****Option A**

**Explaination / Solution: **

No Explaination.

No Explaination.

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Consider a network with five nodes, N1 to N5, as shown below

**A. ** (3. 2, 0, 2, 5)

**B. ** (3, 2, 0, 2, 6)

**C. ** (7, 2, 0, 2, 5)

**D. ** (7, 2, 0, 2, 6)

**Answer : ****Option A**

**Explaination / Solution: **

The net work uses a Distance Vector Routing protocol. Once the routes have
stabilized, the distance vectors at different nodes are as following

N1 : (0, 1, 7, 8, 4)

N2 : (1, 0, 6, 7, 3)

N3 : (7, 6, 0, 2, 6)

N4 : (8, 7, 2, 0, 4)

N5 : (4, 3, 6, 4, 0)

Each distance vector is the distance of the best known path at that instance to
nodes, N1 to N5, where the distance to itself is 0. Also, all links are symmetric
and the cost is identical in both directions. In each round, all nodes exchange
their distance vectors with their respective neighbors. Then all nodes update their
distance vectors. In between two rounds, any change in cost of a link will cause
the two incident nodes to change only that entry in their distance vectors

The cost of link N2-N3 reduces to 2 in (both directions). After the next round of
updates, what will be the new distance vector at node, N3?

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Let X be a recursive language and Y be a recursively enumerable but not recursive language.
Let W and Z be two languages such that Y reduces to W , and Z reduces to X (reduction
means the standard many-one reduction). Which one of the following statements is TRUE?

**A. ** W can be recursively enumerable and Z is recursive.

**B. ** W can be recursive and Z is recursively enumerable.

**C. ** W is not recursively enumerable and Z is recursive.

**D. ** W is not recursively enumerable and Z is not recursive.

**Answer : ****Option C**

**Explaination / Solution: **

No Explaination.

No Explaination.

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